Math From Scratch 15: The Fundamental Theorem of Arithmetic November 1, 2011 The fifteenth lesson of the Math From Scratch series, dealing with the Fundamental Theorem of Arithmetic, is available here. Share this:Click to share on Facebook (Opens in new window)Click to share on Reddit (Opens in new window)Click to share on Tumblr (Opens in new window)Click to share on Twitter (Opens in new window)

I’m enjoying this series. I’m a bit confused by the following statement though

Am I missing some other constraint on these variables? What if I pick p = 7, n = 3, a1 = 1, a2 = 2, and a3 = 3?

No, I missed listing the constraint. It should read that, if p divides the PRODUCT of all n integers, then p must divide one of the integers on the list. I’ll get that corrected and reposted this week.

While on the topic of corrections, should “the result follows from the assumption of the n + 1 case” refer to the case for “n” and not “n + 1”?

Thanks for catching those. Both errors should now be corrected.